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A proton, a deuteron and an alpha particle are accelerated through potentials of $V,\: 2V\: and\: 4V$ respectively. Their velocities will bear a ratio

$\begin {array} {1 1} (a)\;1:1:1 & \quad (b)\;1: \sqrt 2 : 1 \\ (c)\;\sqrt 2 : 1 : 1 & \quad (d)\;1 : 1: \sqrt 2 \end {array}$


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Ans : (d)
velocity,$v = \large\frac{\sqrt{(2qV)}}{ m}$


answered Dec 27, 2013 by thanvigandhi_1
edited Mar 13, 2014 by thanvigandhi_1

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