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The work function of a substance is $4.0\: eV$. The longest wavelength of light that can cause photoelectron emission from this substance is approximately

$\begin {array} {1 1} (a)\;540\: nm & \quad (b)\;400\: nm \\ (c)\;310\: nm & \quad (d)\;220\: nm \end {array}$


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Ans : (c)
work function,$ \phi_{\circ} = hv_{\circ} – \large\frac{hc}{\lambda_{max}}$
$ \Rightarrow \lambda_{max} = \large\frac{hc}{\phi_{\circ}} = \large\frac{1240}{4}$$ = 310\: nm$


answered Dec 27, 2013 by thanvigandhi_1
edited Mar 13, 2014 by thanvigandhi_1

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