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An electron is 2000 times lighter than a proton. Both are moving such that their matter waves have a length of $ 1\: \dot {A}$. The ratio of their kinetic energy in approximation is

$\begin {array} {1 1} (a)\;1:1 & \quad (b)\;1: 2000 \\ (c)\;2000:1 & \quad (d)\;1:200 \end {array}$

 

Can you answer this question?
 
 

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Ans : (c)
Since both have same de Broglie wavelength,
hence both must have equal value of momentum.
Since $E =\large\frac{ p^2}{ pm}$
$ \Rightarrow \large\frac{E_e}{ E_p} = \large\frac{m_p}{ m_e} = 1840 = 2000$
{nearest possible approximation to answer}

 

answered Dec 27, 2013 by thanvigandhi_1
edited Mar 13, 2014 by thanvigandhi_1
 

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