Email
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

An electron is 2000 times lighter than a proton. Both are moving such that their matter waves have a length of $ 1\: \dot {A}$. The ratio of their kinetic energy in approximation is

$\begin {array} {1 1} (a)\;1:1 & \quad (b)\;1: 2000 \\ (c)\;2000:1 & \quad (d)\;1:200 \end {array}$

 

1 Answer

Comment
A)
Ans : (c)
Since both have same de Broglie wavelength,
hence both must have equal value of momentum.
Since $E =\large\frac{ p^2}{ pm}$
$ \Rightarrow \large\frac{E_e}{ E_p} = \large\frac{m_p}{ m_e} = 1840 = 2000$
{nearest possible approximation to answer}

 

Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
...