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The graph between stopping potential vs frequency is given for two different metals, then choose most appropriate statement

$\begin {array} {1 1} (a)\;v_{01} = v_{02}\: and\: \theta_1 = \theta_2 & \quad (b)\;v_{01} > v_{02}\: and\: \theta_1 > \theta_2 \\ (c)\;v_{01} < v_{02}\: and\: \theta_1 < \theta_2 & \quad (d)\;v_{01} < v_{02}\: and\: \theta_1 = \theta_2 \end {array}$

 

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Ans : (d)
At threshold frequency, stopping potential $V_{\circ} = 0.$
From graph it is clear that $ v_{01} < v_{02}, \tan\: \theta$ is slope of curve between $V_{\circ} vs \: v$
So, $ \tan\theta_1 = \tan\theta_2$

 

answered Dec 27, 2013 by thanvigandhi_1
edited Mar 13, 2014 by thanvigandhi_1
 

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