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Three Dimensional Geometry
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find the radius of cicular section of sphere x^2+y^2+z^2=49 by the plane 2x+3y-z-4(14)^1/2
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Dec 28, 2013
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ankitclusters_1
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0
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Find the radius of the circular section of the sphere $x^2+y^2+z^2=49$ cut by a plane $2x+3y-z-5\sqrt{14}=0.$
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Find the equation of the plane through the line of intersection of the planes $x + y + z = 1$ and $2x + 3y + 4z = 5$ which is perpendicular to the plane$x -y + z = 0.$
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Find the equation of the plane passing through the line of intersection of the planes $ 2x+y-z=3 \: and \: 5x-3y+4z+9=0$ and parallel to the line \(\large \frac{x-1}{2}=\frac{y-3}{4}=\frac{z-5}{5}. \)
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Find the equation of the plane which is perpendicular to the plane \( 5x+3y+6z+8=0\) and which contains the line of intersection of the planes \( x+2y+3z-4=0 \: and \: 2x+y-z+3=0.\)
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