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If in a photoelectric experiment, the wavelength of incident radiation is reduced from $6000\: A^{\circ} \: to \: 4000\: A^{\circ}$ , then

(a) Stopping potential will decrease

(b) Stopping potential will increase

(c) KE of emitted electrons will decrease

(d) value of work function will decrease
Can you answer this question?

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Ans : (b)
$ \phi = \large\frac{hc}{ \lambda} - eV_{\circ} \phi =$ work function of a particular metal will remain constant
If $\lambda$ = incident radiation wavelength is increased,
$ V_{\circ}$ = stopping potential also has to increase to keep $ \phi$ constant.


answered Dec 28, 2013 by thanvigandhi_1
edited Mar 13, 2014 by thanvigandhi_1

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