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Graph of $KE_{max}$ of the photoelectrons against v the frequency of the radiation incident on the metal is a straight line of slope equal to: , i

$\begin {array} {1 1} (a)\;work \: function & \quad (b)\;stopping\: potential \\ (c)\;\large\frac{h}{e} & \quad (d)\;h \end {array}$

 

1 Answer

Ans : (d)
Einstein’s photoelectric equation, $ KE_{max} = hv  –  \phi$
i.e, $h$ is the slope.

 

answered Dec 28, 2013 by thanvigandhi_1
edited Oct 30, 2014 by thagee.vedartham
 

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