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The line $\overrightarrow r=(4\hat i+2\hat j+\alpha \hat k)+\lambda(\hat i+\hat j+2\hat k)$ lies on the plane $2x-4y+z=7$ if $\alpha=?$


1 Answer

If a line lies on a plane then every point of the line satisfies the equation of the plane.
A point on the given line is $ (4,2,\alpha)$
This point satisfies the eqn. of the plane $2x-4y+z=7$
$\therefore 8-8+\alpha=7$
answered Dec 28, 2013 by rvidyagovindarajan_1

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