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# Integrate : $\int \large\frac{\cos 2 x}{\sin ^2 x \cos ^2 x }$$dx (a)\;-\cot x -\tan x +c \\(b)\;\cos x +\tan x +c \\(c)\;\cos x - \tan x +c \\ (d)\;\sin x - cosec x +c Can you answer this question? ## 1 Answer 0 votes \int \large\frac{\cos ^2 x -\sin ^2 x }{\sin ^2 x \cos ^2 x }$$dx$
$=\int cosec ^2 x dx-\int \sec^2 x dx$
$=-\cot x -\tan x +c$
Hence a is the correct answer.