Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

When radiation falls on plate C, the ammeter reading remains zero till jockey is moved from the end P to the middle point of the wire PQ. Therefore the deflection is recorded in the ammeter. The maximum kinetic energy of the emitted electron is :

$\begin {array} {1 1} (a)\;2\: eV & \quad (b)\;4\: eV \\ (c)\;8\: eV& \quad (d)\;10\: eV \end {array}$

 

1 Answer

Comment
A)
Ans : (b)
P.D. across the two electrodes when jockey is at the mid point = $4V$
kinetic energy of the emitted electron = $e \times 4V = 4eV$

 

Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...