Chat with tutor

Ask Questions, Get Answers


S1: If momentum of a body increases by 50%, its KE will increase by 125%. S2: KE is proportional to square of velocity.

$\begin{array}{1 1} \text{(a) S1 is true, S2 is true; S2 is correct explanation of S1.} \\ \text{(b) S1 is true, S2 is true; S2 is not correct explanation of S1.} \\\text{(c) S1 is false; S2 is true.} \\ \text{(d) S1 is true; S2 is false.} \end{array}$

1 Answer

Ans : (a)
Momentum $p_2 = p_1+50 \% \: of\: p_1$
$ \Rightarrow p_2 = \large\frac{3}{2} \times p_1$
Since, $KE \sim v^2 \sim p^2$
Hence, $KE_2 = \large\frac{9}{4} KE_1$
So, $ \% $ increase in $KE$ is
$\large\frac{KE_2 – KE_1}{KE_1} \times100 =( { \large\frac{9p_1}{4} – p_1} ) \times100 = 125 \%$


Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.