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# Integrate : $\int \large\frac{3x}{(x+1)(x+2)}$$dx (a)\;6 \log (x+2)-3 \log (x+1)+c \\(b)\;-3\log (x+1)+c \\(c)\; 6 \log 2- 3 \log (x+1) \\ (d)\;None Can you answer this question? ## 1 Answer 0 votes \int \large\frac{3x}{(x+1)(x+2)}$$dx$
first find x value in denominator,
$x=-1,x=-2$
Put x value in denominator and numerator and do put value of x, where infinite condition occured so,