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Let $f:R\rightarrow R$ be a function defined by $f(x)=min\{x+1,\mid x\mid+1\}$. Then which of the following is true ?

$\begin{array}{1 1}(a)\;f(x)\;is\;differentiable\;everywhere\\(b)\;f(x)\;is\;not\;differentiable\;at\;x=0\\(c)\;f(x)\geq 1\;for \;all\;x\in R\\(d)\;f(x)\;is \;not\;differentiable\;at\;x=1\end{array}$

1 Answer

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$\Rightarrow$ Hence f(x) is differentiable everywhere for all $x\in R$
Hence (a) is the correct answer.
answered Dec 31, 2013 by sreemathi.v

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