logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  3-D Geometry
0 votes

The angle between the planes $3x+4y+5z=3$ and $4x-3y+5z=2$ is ?

$\begin{array}{1 1} \frac{\pi}{2} \\ \frac{\pi}{3} \\ \frac{\pi}{4} \\ \frac{\pi}{6} \end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
Toolbox:
  • Angle between the two planes is $cos\theta=\large\frac{\overrightarrow n_1.\overrightarrow n_2}{|\overrightarrow n_1|\:|\overrightarrow n_2|}$
From the equations of the given two planes , $\overrightarrow n_1=(3,4,5)\:and\:\overrightarrow n_2=(4,-3,5)$
$\therefore\:$ Angle between them is given by $cos\theta=\large\frac{(3,4,5).(4,-3,5)}{\sqrt {50}.\sqrt {50}}$
$\Rightarrow\:cos\theta=\large\frac{25}{50}=\frac{1}{2}\:\:\therefore\:\theta=\large\frac{\pi}{3}$
answered Dec 31, 2013 by rvidyagovindarajan_1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...