Browse Questions

# The line $\large\frac{x-2}{3}=\frac{y-3}{4}=\frac{z-4}{5}$ is parallel to the which of the following?

$\begin{array}{1 1} (A) 3x+4y+5z=7 \\ (B) 2x+y-2z=0 \\(C) x+y-z=2 \\ (D)2x+3y+4z=0\end{array}$

Toolbox:
• If the line is parallel to the plane then the line will be $\perp$ to its normal.
Given line is $\large\frac{x-2}{3}=\frac{y-3}{4}=\frac{z-4}{5}$
$d.r.$ of the line is $(3,4,5)$
$(3,4,5).(2,1,-2)=0$
$\Rightarrow\:2x+y-2z=0$ is parallel to the line.