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The line $\large\frac{x-2}{3}=\frac{y-3}{4}=\frac{z-4}{5}$ is parallel to the which of the following?

$\begin{array}{1 1} (A) 3x+4y+5z=7 \\ (B) 2x+y-2z=0 \\(C) x+y-z=2 \\ (D)2x+3y+4z=0\end{array}$

1 Answer

  • If the line is parallel to the plane then the line will be $\perp $ to its normal.
Given line is $\large\frac{x-2}{3}=\frac{y-3}{4}=\frac{z-4}{5}$
$d.r.$ of the line is $(3,4,5)$
$\Rightarrow\:2x+y-2z=0$ is parallel to the line.
answered Dec 31, 2013 by rvidyagovindarajan_1

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