$(a)\;\frac{1}{4\sqrt{4}},\frac{1}{6\sqrt{2}}\qquad(b)\;\frac{1}{\sqrt2},{\sqrt2}\qquad(c)\;\frac{1}{4\sqrt{2}},\frac{1}{8\sqrt{2}}\qquad(d)\;\frac{1}{4},\frac{1}{4\sqrt{2}}$

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