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# The direction ratio of the line $3x+1=6y-2,\:z=1$ is ?

$\begin{array}{1 1} (a)\:\:(2,1,1)\:\:\qquad\:(b)\:\:(1,1,1)\:\:\qquad\:(c)\:\:(3,6,1)\:\:\qquad\:(d)\:\:(2,1,0) \end{array}$

Convert the equation into standard form of the eqn, of line.
$i.e.,$ $\large\frac{x+1/3}{1/3}=\frac{y-1/3}{1/6}=\frac{z-1}{0}=\lambda$