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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class12  >>  Probability
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A fair die is tossed once. The probability that either an even number or 3 will appear

$\begin {array} {1 1} (1)\;\large\frac{4}{5} & \quad (2)\;\large\frac{3}{4} \\ (3)\;\large\frac{2}{3} & \quad (4)\;None\: of \: these \end {array}$


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The favourable number of cases is 4, because getting 2,4,6 and 3
are favourable events.
Hence the required probability is $ \large\frac{4}{6}$
$ = \large\frac{2}{3}$
Ans : (C)
answered Jan 2, 2014 by thanvigandhi_1
edited Aug 11, 2014 by sharmaaparna1

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