A family has 4 children. A child is selected at random from the family. Assuming that there are equal number of boys and girls in the family, the probability that the selected child is a girl is

$\begin {array} {1 1} (1)\;\large\frac{1}{6} & \quad (2)\;\large\frac{1}{4} \\ (3)\;\large\frac{2}{3} & \quad (4)\;\large\frac{1}{2} \end {array}$

There are equal number of boys and girls in the family.
Hence the selected child may be a girl as well as a boy
will equal probability. Therefore the required probability is
$\large\frac{1}{2}$
Ans : (D)
edited Aug 11, 2014