Comment
Share
Q)

# A coin is tossed thrice. The probability of getting head at least once is

$\begin {array} {1 1} (1)\;\large\frac{3}{8} & \quad (2)\;\large\frac{1}{8} \\ (3)\;\large\frac{1}{4} & \quad (4)\;\large\frac{7}{8} \end {array}$

$= 1-P(TTT)$
$=1- \large\frac{1}{2} \times \large\frac{1}{2} \times \large\frac{1}{2}$
$1 - \large\frac{1}{8}$
$= \large\frac{7}{8}$