Browse Questions

# In a throw of two coins, the probability of getting both heads or both tails is

$\begin {array} {1 1} (1)\;\large\frac{1}{4} & \quad (2)\;\large\frac{1}{2} \\ (3)\;\large\frac{3}{4} & \quad (4)\;None\: of \: these \end {array}$

Can you answer this question?

We have P(HH)= $\large\frac{1}{2} \times \large\frac{1}{2}$
$= \large\frac{1}{4}$
Also $P(TT)=\large\frac{1}{2} \times \large\frac{1}{2}$
$= \large\frac{1}{4}$
$\therefore P(HH)+P(TT) = \large\frac{1}{4} + \large\frac{1}{4}$
$= \large\frac{2}{4}$
$\large\frac{1}{2}$
Ans : (2)
answered Jan 2, 2014