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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class12  >>  Probability
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In a throw of two coins, the probability of getting both heads or both tails is

$\begin {array} {1 1} (1)\;\large\frac{1}{4} & \quad (2)\;\large\frac{1}{2} \\ (3)\;\large\frac{3}{4} & \quad (4)\;None\: of \: these \end {array}$

 

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We have P(HH)= $ \large\frac{1}{2} \times \large\frac{1}{2}$
$ = \large\frac{1}{4}$
Also $ P(TT)=\large\frac{1}{2} \times \large\frac{1}{2}$
$ = \large\frac{1}{4}$
$ \therefore P(HH)+P(TT) = \large\frac{1}{4} + \large\frac{1}{4} $
$ = \large\frac{2}{4} $
$ \large\frac{1}{2} $
Ans : (2)
answered Jan 2, 2014 by thanvigandhi_1
 

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