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# Three coins are tossed. The probability that not more than two coins will fall with head upwards is

$\begin {array} {1 1} (1)\;\large\frac{5}{8} & \quad (2)\;\large\frac{7}{8} \\ (3)\;\large\frac{3}{8} & \quad (4)\;None\: of \: these \end {array}$

$= 1 - \large\frac{1}{2} \times \large\frac{1}{2} \times \large\frac{1}{2}$
$1 - \large\frac{1}{8}$
$\large\frac{7}{8}$