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Questions  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Probability
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The probability that in a throw of 12 dice 1,1, 2,2, 3,3, 4,4, 5,5, 6,6 will occur in any sequence is :

$\begin {array} {1 1} (1)\;\large\frac{12!}{2^66^{12}} & \quad (2)\;\large\frac{12!}{6^62^{12}} \\ (3)\;\large\frac{12!}{2^66^{6}} & \quad (4)\;None\: of \: these \end {array}$

 

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