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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Sequence and Series
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If a, b, c are in GP, find the value of $a^2b^2c^2(\large\frac{1}{a^3}+\large\frac{1}{b^3}+\large\frac{1}{c^3})$

$\begin{array}{1 1} a^3 b^3c^3 \\ 1\\\frac{a^3+b^3+c^3}{a^2b^2c^2} \\a^3+b^3+c^3\end{array}$

Can you answer this question?

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Answer : $(d)\;a^3+b^3+c^3$
Explanation : a,b,c are in GP $ \;b^2=ac$
answered Jan 3, 2014 by yamini.v
edited Jan 24, 2014

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