logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

A force F acts between two charges kept 1 cm apart in air. If permittivity of air and dielectric constant of water are $\in _0$ and $K$ respectively, find the force acting when both atoms are placed in water.

$(A)\;\frac{F}{K}\\ (B)\;\frac{F \in _0}{K} \\ (C)\; \frac{F}{K \in _0}\\ (D)\;\frac{FK}{\in _0} $

Can you answer this question?
 
 

1 Answer

0 votes
Force in air $F= \large\frac{1}{4 \pi \in _0} \frac{q_1q_2}{r^2}$
Force in water $F'= \large\frac{1}{4 \pi (k \in _0)} \frac{q_1q_2}{r^2}$
=> $F'= \large\frac{F}{K}$
Hence A is the correct answer.
answered Jan 3, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...