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In a medium of dielectric constant K, the electric field is $\overrightarrow {E}$, if $\in _0$ is permittivity of free space , the electric displacement vector is :

$(A)\;\frac{K \overrightarrow{E}}{\in _0}\\ (B)\;K \in _0 \overrightarrow {E} \\ (C)\; \frac{\overrightarrow{E}}{K \in _0}\\ (D)\;None $

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Electric displacement vector
$\overrightarrow {D}= \;\in \overrightarrow {E}$
$\in\; =\;\in _0 K$
=> $\overrightarrow {D} =K \in _0 \overrightarrow {E}$
Hence B is the correct answer.
answered Jan 3, 2014 by meena.p

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