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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Sequence and Series
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Find the sum of the series $3^2$ + $5^2$ + $7^2$ +-----upto 10 terms

$\begin{array}{1 1} 1660 \\ 679 \\ 1770 \\ 1540 \end{array}$

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Answer : (c) 1770
Explanation :
$T_{n}=(2n+1)^2$
$\sum\;T_{n}=(2n+1)^2$
$=\sum\;(4n^2+4n+1)$
$S_{n}=\large\frac{4n(n+1)(2n+1)}{6}+4\large\frac{n(n+1)}{2}+n$
$S_{10}=\large\frac{4*10*11*21}{6}+4*\large\frac{10*11}{2}+10$
$=1540+220+10$
$=1770.$
answered Jan 3, 2014 by yamini.v
edited Jan 24, 2014
 

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