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Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Probability

A and B throw a die. The probability that A's throw is not greater than B's is :

$\begin {array} {1 1} (1)\;\large\frac{1}{2} & \quad (2)\;\large\frac{1}{6} \\ (3)\;\large\frac{7}{12} & \quad (4)\;\large\frac{5}{12} \end {array}$

 

1 Answer

If B throws 1 then A can throw only 1.
If B throws 2 then A can throw only 1 and 2
$ \therefore $ Required probability = $ \large\frac{1}{6}.\large\frac{1}{6}+\large\frac{1}{6}.\large\frac{2}{6}+\large\frac{1}{6}.\large\frac{3}{6}+\large\frac{1}{6}.\large\frac{4}{6}+\large\frac{1}{6}.\large\frac{5}{6}+\large\frac{1}{6}.\large\frac{6}{6}$
$ \large\frac{1}{36} [ 1+2+3+4+5+6]$
$ \large\frac{1}{36} \times 21$
$ = \large\frac{7}{12}$
Ans : (3)
answered Jan 3, 2014 by thanvigandhi_1
 

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