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JEEMAIN and NEET
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Physics
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Class12
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Electrostatic Potential and Capacitance
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Q)
A $0.4 \mu F$ capacitor is charged to $1200 v. $ After removing battery a $0.2 \mu F$ capacitor is connected in parallel to it. The voltage on capacitor will become :
$(A)\;200 \\ (B)\;600 \\ (C)\; 1200 \\ (D)\;800 $
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