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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  3-D Geometry
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If $O$ is origin, $OP=3$ with $d.r.=(-1,2,-2)$ then the coordinate of $P$ is ?

$\begin{array}{1 1} (-1,2,-2) \\ (1,2,2) \\ (3,6,-9) \\ (\frac{-1}{9}, \frac{2}{9},\frac{-2}{9} ) \end{array} $

Can you answer this question?
 
 

1 Answer

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Given: $d.r.$ of $\overrightarrow{OP}=(-1,2,-2)$
$\Rightarrow\:P(-1,2,-2)$
answered Jan 3, 2014 by rvidyagovindarajan_1
 

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