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Prove that the curves \( y^2 = 4x\) and \( x^2 = 4y\) divide the area of the square bounded by \( x = 0, x = 4, y = 4\) and \(y = 0\) into three equal parts.
cbse
class12
modelpaper
2012
sec-c
q34
math
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Dec 29, 2012
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thanvigandhi_1
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Prove that the curve \( y^2=4x\) and \( x^2=4y\) divide the area of the square bounded by \( x=0,x=4,y=4\: and \: y=0\) into three equation.
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Jan 30, 2013
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Using integration, find the area of the region bounded by the parabola \( y^2=4x\) and the circle \( 4x^2+4y^2=9\)
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Find the area of the region enclosed between the two circles \(x^2+ y^2 = 4\) and \((x – 2)^2 + y^2 = 4\).
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Dec 22, 2012
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Using integration find the area of the region bounded by the parabola \( y^2 = 4x \) and the circle \( 4x^2 + 4y^2 = 9 \).
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Dec 19, 2012
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Prove that \( tan^{-1} \bigg(\frac{\large 1}{\large 4} \bigg) + tan^{-1} \bigg( \frac{\large 2}{\large 9} \bigg ) = \frac{\large 1}{\large 2} cos^{-1} \bigg( \frac{3}{5} \bigg). \)
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