# A,B and C take one shot each at a target. Their probability of hitting the target are respectively 0.4, 0.5 and 0.8. The probability that at least two of them hit the target is

$\begin {array} {1 1} (A)\;\large\frac{3}{5} & \quad (B)\;\large\frac{13}{25} \\ (C)\;\large\frac{9}{25} & \quad (D)\;None\: of \: these \end {array}$

$P(\overline ABC)+P(A \overline BC) +P(AB \overline C) + P(ABC)$
$= 0.6 \times 0.5 \times 0.8 + 0.4 \times 0.5 \times 0.8 \times$
$+ 0.4 \times 0.5 \times 0.2 + 0.4 \times 0.5 \times 0.8$
$= 0.6$
$= \large\frac{3}{5}$
Ans : (A)