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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class12  >>  Probability
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A,B and C take one shot each at a target. Their probability of hitting the target are respectively 0.4, 0.5 and 0.8. The probability that at least two of them hit the target is

$\begin {array} {1 1} (A)\;\large\frac{3}{5} & \quad (B)\;\large\frac{13}{25} \\ (C)\;\large\frac{9}{25} & \quad (D)\;None\: of \: these \end {array}$

 

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$ P(\overline ABC)+P(A \overline BC) +P(AB \overline C) + P(ABC)$
$ = 0.6 \times 0.5 \times 0.8 + 0.4 \times 0.5 \times 0.8 \times $
$+ 0.4 \times 0.5 \times 0.2 + 0.4 \times 0.5 \times 0.8$
$ = 0.6$
$ = \large\frac{3}{5}$
Ans : (A)

 

answered Jan 3, 2014 by thanvigandhi_1
 

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