Email
logo

Ask Questions, Get Answers

X
 
Questions  >>  CBSE XII  >>  Math  >>  Model Papers
Answer
Comment
Share
Q)

Find the equation of the plane passing through the points ( 1, 2, 3 ) and (0, -1, 0 ) and parrallel to the line, \( \large\frac{x-1}{2} = \frac{y+2}{3} = \frac{z}{-3} \).

1 Answer

Comment
A)
Equation of the plane passing through  point (1,2,3) is

a(x-1)+ b(y-2)+c(z-3)=0 ..........(1)

Equation of the plane passes through (0,-1,0)

 Hence putting in equation in (1)

-a-3b-3c=0.............(2)

The equation of the plane parrallal to the given line

(x-1)/2=(y+2)/3=(z-0)/-3

Normal to the plane is parpendicular to the given line

 So 2a+3b-3c=0.........(3)

a=6k, b=-3k, c=k

 Putting the value in equation (1)

6k(x-1)+-3k(y-2)+k(z-3)=0

=> 6x-6+3y-6+z-3=0

=> 6x+3y+z=9
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
...