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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class12  >>  Probability
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A die is thrown 4 times. The probability of getting at most two 6 is :

$\begin {array} {1 1} (A)\;0.984 & \quad (B)\;0.802 \\ (C)\;0.621 & \quad (D)\;0.721 \end {array}$

 

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1 Answer

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Here $ P = \large\frac{1}{6}$
$ Q = \large\frac{5}{6}$
$ = 4C_0Q^4+4C_1PQ^3+4C_2P^2Q^2$
$ \large\frac{425}{432}$
$ = 0.984$
Ans : (A)
answered Jan 4, 2014 by akashraman249_1
edited Jan 6, 2014 by thanvigandhi_1
 

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