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# A die is thrown 4 times. The probability of getting at most two 6 is :

$\begin {array} {1 1} (A)\;0.984 & \quad (B)\;0.802 \\ (C)\;0.621 & \quad (D)\;0.721 \end {array}$

Here $P = \large\frac{1}{6}$
$Q = \large\frac{5}{6}$
$= 4C_0Q^4+4C_1PQ^3+4C_2P^2Q^2$
$\large\frac{425}{432}$
$= 0.984$
Ans : (A)
edited Jan 6, 2014