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# Which term of the sequence 130,126,122----- is the first negative term.

$\begin{array}{1 1} -1 \\ -4 \\ -2 \\ -6 \end{array}$

$t_{n}=130-4(n-1)\;<\;0$
$130\;<\;4(n-1)$
$\frac{65}{2}\;<\;n-1$
$n\;>\frac{65}{2}+1\;=\;\frac{67}{2}=33.5$
$n=34\;is\;the\;1^{st}\;negative\;term$
$t_{n}=130-4(33)130-132=-2.$