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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Sequence and Series
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How many two digit numbers are divisible by 4?

$\begin{array}{1 1} 20 \\ 25 \\ 22 \\ 21 \end{array}$

Can you answer this question?
 
 

1 Answer

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Answer : (c) 22
Explanation :
2 digit numbers 10 to 99 first 2 digit number divisible by 4 is 12. Last 2 digit no divisible by 4 => 96
$sequence\; is \;12,16,20\;------\;96$
$n\;is\;the\;number\;of\;terms\;in\;the\;above\;AP$
$a=12\;,t_{n}=96\;,d=4$
$t_{n}=12+(n-1)\;96$
$4(n-1)=84$
$n-1=\frac{84}{4}=21$
$n=22.$
answered Jan 5, 2014 by yamini.v
 

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