$\begin{array}{1 1} 100 \\ 996 \\ 128 \\ 129 \end{array}$

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Answer : (d) 129

Explanation : 3 digit numbers are between 100 and 999. First 3 digit number to leave a remainder of 2 when divided by 7 is 100.

Last 3 digit number to leave a remainder of 2 when divided by 7 is 996. it is an AP with

$a=100\;,d=7\;,t_{n}=996$

$t_{n}=996=100+7(n-1)$

$896=7(n-1)$

$128=n-1$

$n=129.$

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