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Equivalent capacity of parallel plate capacitor shown below is :

 

$(A)\;\frac{\in _0 A}{\bigg(\frac{d_1}{k_1}+ \frac{d_2}{k_2}+\frac{d_3}{k_3}\bigg)} \\ (B)\;\frac{\in _0 A}{\bigg(\frac{d_1+d_2+d_3}{K_1+k_2+k_3}\bigg)} \\ (C)\; \frac{\in _0 A k_1k_2k_3}{d_1d_2d_3} \\ (D)\;None $

1 Answer

By using property
we get
=>$\frac{\in _0 A}{\bigg(\frac{d_1}{k_1}+ \frac{d_2}{k_2}+\frac{d_3}{k_3}\bigg)}$
Hence A is the correct answer.
answered Jan 6, 2014 by meena.p
 

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