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Probability
Let A,B,C be three equally likely and collectively exhaustive events. If the odds 8 : 3 against A, 5:2 against B then the odds against C are
$\begin {array} {1 1} (A)\;20:17 & \quad (B)\;50:31 \\ (C)\;3:34 & \quad (D)\;77:34 \end {array}$
jeemain
math
cbse
class12
probability
probability-distribution-of-a-random-variable
easy
q26
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asked
Jan 6, 2014
by
thanvigandhi_1
retagged
Sep 16, 2014
by
sharmaaparna1
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1 Answer
$P(A)=\large\frac{3}{11}$
$ P(B)=\large\frac{2}{7}$
$P(C)=1-(P(A)+P(B))$
$=1-\bigg( \large\frac{3}{11}+\large\frac{2}{7} \bigg)$
$ = \large\frac{34}{77}$
Odds against C are 43 : 34
answered
Jan 6, 2014
by
thanvigandhi_1
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