logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class12  >>  Probability
0 votes

A fair coin is tossed 100 times. The probability of getting tails on odd number of times is

$\begin {array} {1 1} (A)\;\large\frac{1}{2} & \quad (B)\;\large\frac{1}{8} \\ (C)\;\large\frac{3}{8} & \quad (D)\;None\; of \: these \end {array}$

 

Can you answer this question?
 
 

1 Answer

0 votes
Total number of cases = $ 2^{100}$
Number of favourable cases = $ 100C_1+100C_3+....100C_{99}$
$ = 2^{100-1}$
$ = 2^{99}$
$ \therefore$ Required probability = $ \large\frac{2^{99}}{2^{100}}$
$ \large\frac{1}{2}$
Ans : (A)
answered Jan 6, 2014 by thanvigandhi_1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...