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Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Probability

A fair coin is tossed 100 times. The probability of getting tails on odd number of times is

$\begin {array} {1 1} (A)\;\large\frac{1}{2} & \quad (B)\;\large\frac{1}{8} \\ (C)\;\large\frac{3}{8} & \quad (D)\;None\; of \: these \end {array}$

 

1 Answer

Total number of cases = $ 2^{100}$
Number of favourable cases = $ 100C_1+100C_3+....100C_{99}$
$ = 2^{100-1}$
$ = 2^{99}$
$ \therefore$ Required probability = $ \large\frac{2^{99}}{2^{100}}$
$ \large\frac{1}{2}$
Ans : (A)
answered Jan 6, 2014 by thanvigandhi_1
 

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