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Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Probability

The chance of throwing a total of 3 or 5 or 11 wih two dice is

$\begin {array} {1 1} (A)\;\large\frac{5}{36} & \quad (B)\;\large\frac{1}{9} \\ (C)\;\large\frac{2}{9} & \quad (D)\;\large\frac{19}{36} \end {array}$

 

1 Answer

3 can be thrown as (1,2)(2,1)
5 can be thrown as (1,4)(4,1)(2,3)(3,2)
11 can be thrown as (5,6)(6,11)
$ \therefore $ Required probability = $ \large\frac{8}{36}$
$ = \large\frac{2}{9}$
Ans (C)
answered Jan 6, 2014 by thanvigandhi_1
 

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