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A dielectric slab is introduced just to fill up the space between plates of parallel plate capacitor. The capacitor is charged and then disconnected . The slab is then slowly drown out . The plot of potential difference across the plates and length of dielectric slab drawn out looks like :

$\begin{array}{1 1} (A) \\ (B) \\ (C) \\ (D) \end{array}$

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Potential difference V increases exponentially when slab is drawn out but becomes constant when slab is completely removed.
Hence B is the correct answer.
answered Jan 6, 2014 by meena.p
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