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An alpha particle is accelerated by a potential difference of $10^7 V$. Its kinetic energy will be

$(A)\;20 \;Mev \\ (B)\;10\; Mev \\ (C)\; 40\; Mev \\ (D)\;80\;Mev $

1 Answer

$K.E= qV$
$\qquad= 2 \times 1.6 \times 10^{-19} \times 10^7 \;J$
$\qquad= 2 \times 10^7 ev$
$\qquad= 20 \;Mev$
Hence A is the correct answer.
answered Jan 6, 2014 by meena.p
 

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