Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

$1.387g$ of a sample containing KCl and $NH_4Cl$ is heated until constant weight.The residue is dissolved in 20ml of N/10 $AgNO_3$ solution.Calculate % of chlorine in mixture.


Can you answer this question?

1 Answer

0 votes
Weight of KCl='a'g
Weight of KCl='b'g
On heating
$KCl\rightarrow $No change
$NH_4Cl\rightarrow NH_3\uparrow +HCl \uparrow$
The residue is only KCl,which reacts with $AgNO_3$
Meq of KCl=Meq of $AgNO_3$
$\large\frac{a}{74.5}$$\times 1000$$=20\times \large\frac{1}{10}$
$\large\frac{w}{35.5}$$\times 1000=\large\frac{0.149}{74.5}$$\times 1000+\large\frac{1.238}{53.5}$$\times 1000$
% of $Cl$ in mixture=$\large\frac{0.892}{1.387}$$\times 100$
$\Rightarrow 64.31\%$
Hence (d) is the correct answer.
answered Jan 7, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App