# Differentiate the following w.r.t $x$ : $\sec^{-1}\bigg(\Large \frac{1}{4x^3-3x}\bigg),\normalsize 0 < x <\Large \frac{1}{\sqrt 2}$
$\begin{array}{1 1} \frac{3}{\sqrt {1-x^2}} \\ \frac{-3}{\sqrt {1-x^2}} \\ \frac{3}{\sqrt {1+x^2}} \\ 3\sqrt {1-x^2} \end{array}$