$(a)\;1.5g/ml\qquad(b)\;1.288g/ml\qquad(c)\;2.3g/ml\qquad(d)\;2.64g/ml$

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KOH solution is 30% by weight

Weight of KOH=30g

Weight of the solution=100g

$\therefore$ Volume of the solution=$\large\frac{100}{d}$ ; where, $d$ is density of the solution.

Molarity = 6.90 = $\large\frac{30}{56\times \Large\frac{100}{1000\times d}}$

By solving, we obtain, d = 1.288g/ml

Hence (b) is the correct answer.

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