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Calculate molality of 1 litre solution of $93\%$ $H_2SO_4$ by volume.The density of solution is $1.84\; g$ $mL^{-1}$


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Given, $H_2SO_4$ is 93% by volume
Weight of $H_2SO_4$ = 93 g
Volume of the solution = 100 mL
Weight of the solution = $100\times 1.84 =1.84\;g$
Weight of water = 184 - 93 = 91 g
Molality=$\large\frac{Mole}{Weight\; of\; water\; in\; kg}$
Hence (c) is the correct answer.
answered Jan 7, 2014 by sreemathi.v
edited Mar 18, 2014 by mosymeow_1

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