$(a)\;1.64\qquad(b)\;1.88\qquad(c)\;1.22\qquad(d)\;1.45$

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Mass % of $H_2SO_4=29\%$

(i.e) 100g solution contains 29g $H_2SO_4$

Let the density of solution (in g/ml) is d

Molarity of solution=$\large\frac{\text{Moles of }H_2SO_4}{\text{Volume of solution(ml)}}$$\times 1000$

(M=3.60)

$\large\frac{\Large\frac{29}{98}}{\Large\frac{100}{d}}$$\times 1000=3.60$

$d=1.22g/ml$

Hence (c) is the correct answer.

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