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$1.575g$ of oxalic acid $(COOH)_2xH_2O$ are dissolved in water and the volume made upto 250ml.On titration 16.68ml of this solution requires 25ml of N/15 NaOH solution for complete neutralization.

$(a)\;3\qquad(b)\;1\qquad(c)\;2\qquad(d)\;.5$

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Meq of oxalic acid in 16.68ml=Meq of NaOH
$\Rightarrow 25\times \large\frac{1}{15}$
Meq of oxalic acid in 250ml
$\Rightarrow 25\times \large\frac{1}{15}\times \frac{2.50}{16.68}$
$\Rightarrow 24.98$
$\Rightarrow \large\frac{1.575}{\Large\frac{(90+18x)}{2}}$$\times 1000=24.98$
$x\approx 2$(approx)
Hence (c) is the correct answer.
answered Jan 7, 2014 by sreemathi.v
 

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