$(a)\;3\qquad(b)\;1\qquad(c)\;2\qquad(d)\;.5$

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Meq of oxalic acid in 16.68ml=Meq of NaOH

$\Rightarrow 25\times \large\frac{1}{15}$

Meq of oxalic acid in 250ml

$\Rightarrow 25\times \large\frac{1}{15}\times \frac{2.50}{16.68}$

$\Rightarrow 24.98$

$\Rightarrow \large\frac{1.575}{\Large\frac{(90+18x)}{2}}$$\times 1000=24.98$

$x\approx 2$(approx)

Hence (c) is the correct answer.

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